1: (3+A+B)\Xb2, 2: (3b-4a) (3b-4a), 3(-4a+B)(4at B), 4(2-A)(4-A), 5(4a\Xb3-5b\Xb2)(4a\Xb3+5b\Xb2), 6(5b\Xb2+7a\Xb2)(-5b\Xb2+A\Xb2),
1: (3+a+b)²
2: (3b-4a) (3b-4a)
3(-4a+b)(4at b)
4(2-a)(4-a)
5(4a³-5b²)(4a³+5b²)
6(5b²+7a²)(-5b²+a²)
Answer and Step-by-step explanation:
1. (3+a+b)²
=(3+a+b)(3+a+b)
=(3)(3)+(3)(a)+(3)(b)+(a)(3)+(a)(a)+(a)(b)+(b)(3)+(b)(a)+(b)(b)
=9+3a+3b+3a+a²+ab+3b+ab+b²
=a²+2ab+b²+6a+6b+9
2. (3b−4a)(3b−4a)
=(3b)(3b)+(3b)(−4a)+(−4a)(3b)+(−4a)(−4a)
=9b²−12ab−12ab+16a²
=16a²−24ab+9b²
3.(−4a+b)(4a+b)
=(−4a)(4a)+(−4a)(b)+(b)(4a)+(b)(b)
=−16a²−4ab+4ab+b²
=−16a²+b²
4.
(2−a)(4−a)
=(2)(4)+(2)(−a)+(−a)(4)+(−a)(−a)
=8−2a−4a+a²
=a²−6a+8
5.(4a³−5b²)(4a³+5b²)
=(4a³)(4a³)+(4a³)(5b²)+(−5b²)(4a³)+(−5b²)(5b²)
=16a⁶+20a³b²−20a³b²−25b⁴
=16a⁶−25b⁴
6.(5b²+7a²)(−5b²+a²)
=(5b²)(−5b²)+(5b²)(a²)+(7a²)(−5b²)+(7a²)(a²)
=−25b⁴+5a²b²−35a²b²+7a⁴
=7a⁴−30a²b²−25b⁴
#JuneChallenge
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